Question

The potential energy ofva body of mass 0.5 kg increases by 100 j when it is taken to the top of a tower from ground . if force of gravity on 1kg is 10n , what is the height of the tower ? ( numericals)

Answer 1

Force of gravity on 1kg is 10 N
F = mg
10 = 1 * g
g = 10 m/s^2

Change in Potential energy = mg * ( h2 - h1 )
= mg * ( h - 0 )
= mgh

100 = mgh
h = 100 / mg
h = 100 / (0.5 * 10)
h = 20 m

Height of the tower is 20 m

Answer 2

Answer:

m = 0.5 kg

g = 10 N

h = ?

. .

. PE = mgh

. .

. 100 = 0.5 × 10 × h

=> 5h = 100

=> h = 20

Explanation:

Hence, height = 20m