The potential energy stored in a spring is U when it is stretched for length 10 cm. If the spring is stretched for the next 10 cm then the change in its potential energy is equal to the:
a.3U
b.4U
c.2U
d.None of these
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Answer:
Correct option is 4U
Explanation:
Correct option is B)
For 1st situation,
E=
2
1
k(10×10
−2
)
2
........ (i)
For 2nd situation,
E
′
=
2
1
k(20×10
−2
)
2
........ (ii)
On comparing Eqs. (i) and (ii), we get
E
′
=4E
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