Question

The potential energy "u"of a particle varies with
distance x from a fixed origin as
$u = a \sqrt{x} \div x + b$
where A and B are constants. The dimensions of A and
B are respectively

(1) [ML^5/2T^-2], [L]
(2) [MLT^-2], [L^2]
(3) [L], [ML^3/2 T^-2]
(4) [L^2], [MLT^-2]

with solution​

Answer 1

Answer:

— u = a \sqrt{x} \div x + b where A and B are constants. The dimensions of A and. B are respectively (1) [ML^5/2T^-2], [L] (2) [MLT^-2], [L ^2]

Explanation:

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