Physics, asked by Anonymous, 1 year ago

the potential gradient between the two charged plates having separation, of 0.5 cm and potential difference of 12 volts is :-

143Raj: hii

Answers

Answered by Anonymous

We know that electric field strength is the negative gradient of potential.

⇒ E = -(dV/dr)

given that the potential difference is 12 volts and distance between the two charged plates is 0.005 metre.

substituting we get

⇒ E = -(12/0.005) = -2400 Vm⁻¹

⇒ As Potential Gradient is negative of the Electric field stength.

⇒ The Potential gradient between the two plates = 2400 Vm⁻¹

Anonymous: pardon me for asking this. .is my solution incorrect?

Anonymous: sorry. .i saw you re-asking the same question. .thought my solution was wrong. .so you opted to ask it again.

Anonymous: oh. .thank you for clearing me about this. .i was thinking for a while. .that did i make a mistake somewhere.

Anonymous: okay. .please don't mine about saying this to you. .the question you answered. .n = 3 and l = 2 and m = +2 represents only one orbital.

Anonymous: i mean this question: The following quantum no.s are possible for how many orbitals : n=3, l=2, m=+2 1)1 2)2 3)3 4)4

Anonymous: please pardon me. .i said it because you will be able to know the concept more clearly.

Previous Question

Next Question