Question

the potential of a charged drop is V . This is divided into n smaller drops , then each will have the potential as

Answer 1

Each drop will have potential V

Answer 2

Answer:

let us consider big drop of radius 'R' and  small drop of radius' r'

                 

Explanation:                        

hence, 4/3 pi R3 = n 4/3 pi r3

                                         R3=nr3

                                            R= n raised to 1/3 r

                                             r = R/n raised to 1/3

                                              r= n raised to -1/3 R

potential of smaller drop, v = k q/r

                                           v= kq/ n raised to -1/3 R

 for small drop q is less  ,that is   q = q/n

                                            v =  k q/n / n raised to - 1/3 R

                                               =  k q/n * 1/n raised to - 1/3 R

                                                =k q/n raised to 2/3 R

                                                 = k q/R * n raised to - 2/3

                                                 = n raised to 2/3 * v

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