The potential of a hydrogen electrode at ph = 10 is
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Answer:
Step-by-step explanation:
p H = 10
Using formula [H+] = 10-pH
So [H+] = 10-10 M
Electrode reaction will be
H+ + e- → ½ H2
Use the formula
Value of E0 = 0
Ecell = E0 - 0.0591 log[H2] by
1 [H+]
Ecell = - 0.0591 log( 1/10-10) by
1
Ecell = - 0.0591 ( 10) by
1
-0.591 V
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