Question

The potential of a point B (-20 m, 30 m) taking the potential of a point A (30 m, -20 m) to be zero in an electric field ⃗ = 10xî – 20ĵ NC-1is​

Answer 1

3500 V

Explanation:

Given that,

Potential placed at point A(30, -20) = 0

having E = (10x i - 20 j)

To find;

Potential placed at point B(-20, 30) = ?

Using the formulae,

$v_{BA} = v_{B} - v_{A}$ =  - $∫^{A} _{B}$

By putting the values in the above formula, we get

= -10 ((20² - 30²)/2) + 20 (30 + 20)

= (-5) * (-500) + 1000

= 2500 + 1000

∵ 3500 volts

Thus, 3500 V is the potential of point B(-20, 30).

Learn more: Potential of a point

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