Question

The potential solutions to the radical equation are a = −4 and a = −1.

Answer 1

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Practice question 1

Caleb is solving the following equation for xxx.

x=\sqrt{x+2}+7x=x+2​+7x, equals, square root of, x, plus, 2, end square root, plus, 7

His first few steps are given below.

\begin{aligned}x-7&=\sqrt{x+2}\\ \\ (x-7)^2&=(\sqrt{x+2})^2\\ \\ x^2-14x+49&=x+2 \end{aligned}x−7(x−7)2x2−14x+49​=x+2​=(x+2​)2=x+2​