Physics, asked by pathuribhavishya, 2 days ago

The potential the post A relative to the ground is +100V and the Potential of B relative to the grond is-112V, Work needed to move a charge of+4C from A to B​

Answers

Answered by bindumaradana
0

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Answered by archanajhaa
0

Answer:

The work needed to move a charge of +4C from A to B​ is -848J.

Explanation:

The work done in electrostatics is defined as the product of charge and the change in potential the charge has to go through. i.e.

W=Q\Delta V            (1)

Q=charge

ΔV=change in potential,

As per the question,

Q=4C

Vа=100V

Vь=-112V

\Delta V=V_b-V_a

\Delta V=-112-100=-212V      (2)

By putting equation (2) and Q in equation (1) we get;

W=4\times -212=-848J

Hence, the work needed to move a charge of +4C from A to B​ is -848J.

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