The potentialdifferenceof a x ray tube is 5 kv and current through it is 3.2 then number
Answers
Answered by
0
Solution :
n=It/e
=3.2×10^−3×1/1.6×10^−19
=2×1016
n=It/e
=3.2×10^−3×1/1.6×10^−19
=2×1016
Similar questions