The power delivered to resistor
connected across a cell of emf E with
negligible internal resistance is P. If L is
the length of the resistor and r is the
radius of its cross section, then the
resistivity of the material of the resistor is
Answers
Explanation:
The total resistance of a circuit connected to the given cell of emf 15 V is the sum of all the resistances from various sources like, resistors, ammeter, voltmeter, etc., connected in series along with the internal resistance of the cell.
In this case, the total resistance is given as 3Ω+3Ω+6Ω=12ohms.
From the ohm's law the total current can be calculated from the formula I=V/R.
That is, I=
R
V
=
12A
15V
=1.25A.
Hence, the current through the battery is 1.25 amperes.
The voltage output of a device is measured across its terminals and is called its terminal voltage V. Terminal voltage is given by the equation V=emf−Ir where, r is the internal resistance and I is the current flowing at the time of the measurement.
Therefore, V=15V−(1.25×3)=11.25V.
Hence, the potential difference across the terminals of the cell is 11.25V
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