Question

The power developed by a turbine in a certain steam plant is 1200 kW. The heat supplied to the steam in the boiler is 3360 kJ/kg, the heat rejected by the system to cooling water in the condenser is 2520 kJ/kg and the feed pump work required to pump the condensate back into the boiler is 6 kW. Calculate the steam flow round the cycle in kg/s.

Answer 1

Answer:

Solution.

Q_b=3000KJ/kg;Q

b

=3000KJ/kg;

Q_c=2000KJ/kg;Q

c

=2000KJ/kg;

W_t=1500KW;W

t

=1500KW;

W_p=50KW;W

p

=50KW;

Q=Q_b-Q_c;Q=Q

b

−Q

c

;

Q=3000KJ/kg-2000KJ/kg=1000KJ/kg;Q=3000KJ/kg−2000KJ/kg=1000KJ/kg;

W=W_t-W_p;W=W

t

−W

p

;

W=1500KW-50KW=1450KW;W=1500KW−50KW=1450KW;

\dfrac{W}{Q}=\dfrac{1450KW}{1000KJ/kg}=1.45kg/s;

Q

W

=

1000KJ/kg

1450KW

=1.45kg/s;

Answer:\dfrac{W}{Q}=1.45kg/s.

Q

W

=1.45kg/s.