Question

The power dissipated in the following circuit is

1) 32W
2) 16W
3) 48W
4) 64W​

Answer 1

Answer:

first calculate the equivalent resistance

for 6 ohm resistor

1/R = 1/6 + 1/6 = 1/3

so R = 3 ohm

now for 8 ohm resistor

1/r = 1/8 + 1/8 = 1/4

r = 4 ohm

Total resistance = R + r +1. = 3+4+1 = 8 ohm

power = v^2/resistance

= (16)^2 / 8 = 32 watt