The power dissipation in each of three parallel branches is i w. What is the total power dissipation of the circuit?
Answers
Answer: Total power in a parallel circuit is WT=W1 + W2 + W3 + W4.
Explanation:
Power dissipation = No of branches * power transmission in the branch = 4 * 1.2w = 4.8w Total power in a parallel circuit is WT=W1 + W2 + W3 + W4. The sum of the power lost by each individual resistance will equal the total power lost. Power dissipated can be calculated using combinations of the power formula and Ohm's law depending on the quantities that are known (or any other unknown value.
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Answer:
A transistor's power dissipation is equal to the sum of its collection current + collector-emitter voltage at any given moment. Transistors are rated as to how many watts each may safely dissipate without suffering harm, just like resistors.
The rate of energy dissipation when a flow of I coulombs / second passes through a voltage differential of V volts is IV, which may also be expressed (using Ohm's law) as I2R or V2/R.
Explanation:
The supplied power necessary to run the specified logic function is referred to as power dissipation. The energy provided from another gate is not included in this parameter. In general, a IC with four terminals will need four times as much power from its power source as each gate dissipates.
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