Question

The power factor of an ac circuit is given by

Answer 1

Answer:

The power factor of an ac circuit is given the power factor of an AC circuit is defined as the ratio of the real power (W) consumed by a circuit to the apparent power (VA) consumed by the same circuit. This so gives us: $Power Factor = Real Power/Apparent Power$, or $p.f. = W/VA$.

Explanation:

Power factor is defined as the ratio of the midpoint power in an ac circuit to the detectable power, which is the product of the voltage and current quantity. Power factor (PF) has a value in the middle of zero and unity. Power Factor is a quantify of how effectively incoming power is used in your electrical technique (energy efficiency) and is defined as the ratio of Real (working) power to noticeable(total) power. Real Power (kW) is the power that to all intents and purposes powers the equipment and performs useful fruitful work. It is found by multiplying $(kVA = V \times A)$. The result is communicated as kVA units. PF communicates the ratio of true power used in a circuit to the noticeable power delivered to the circuit.

Hence, the correct answer is $Power Factor = Real Power/Apparent Power$ or $p.f. = W/VA$.

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Answer 2

Power factor = W/VA is the right answer.

Explanation:

• Power factor (PF) is the ratio of working power, measured in kilowatts (kW), to obvious power, measured in kilovolt amperes (kVA).
• Apparent energy, additionally referred to as demand, is the degree of the quantity of energy used to run equipment and system at some point in a sure period.
• It is located with the aid of using multiplying (kVA = V x A). The end result is expressed as kVA units.
• The energy issue of an AC circuit is described because of the ratio of the actual energy (W) consumed with the aid of using a circuit to the obvious energy (VA) consumed with the aid of using the equal circuit.
• This, therefore, offers us: Power Factor = Real Power/Apparent Power, or P.F = W/VA.
• Power issue, cosϕ= R/Z.
• When the circuit carries the handiest resistance, then Z=R, Therefore, cosϕ=1.
• When the circuit carries the handiest inductance, then R=0, Therefore, cosϕ=0.

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