Physics, asked by mrstranger2me, 11 months ago

The power factor of the following circuit will be-
Xc=4022
200V
SR=4022
50Hz
elleill
XL=10092
r= 4092
(2) 0.4 (3) 0.6
(1) 0.2
(4) 0.8

Answers

Answered by aravindareddyaramati

2

Answer:

Xc=4022

200v

SR=4022

50Hz

XL=10092

r=4092

(4)0.8

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