the power generated across 3ohm in the network is??
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Answer:
For 3Ω resistance heat =
R
V
2
=12J
V
2
=12×R=36
V=
36
For upper branch in parallel combination
R
net
=6Ω,V=6V
i=
R
V
=
6
6
=1A
Heat produced in 4Ω
P=H=L
2
R=1
2
(4)=4J
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