the power generated by an electrical circuit (in watts) as a function of its current c (in amperes) is modeled by: p(c)=-20(c-3)^2 +180 which currents will produce no power ?
lower current: ___________ amperes
high current: ___________ amperes
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Answer:
Lower current: 0 amperes
High current: 6 amperes
Step-by-step explanation:
Given that it produces no power or 0 power means P(c)=0
So we have,
⇒ -20(c-3)^2+180=0
⇒ 20(c-3)^2=180 (Cancelling minus on both sides)
⇒ (c-3)^2=180/20
⇒ (c-3)^2=9
⇒ (c-3)=±√9
⇒ (c-3)=±3
Case 1: (c-3)=-3
⇒ c=-3+3
⇒ c=0
Case 2: (c-3)=+3
⇒ c=3+3
⇒ c=6
So, the answer is Lower current: 0 amperes and Higher current: 6 amperes.
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