Question

the power of a 220V, 100W electric bulb working at 110V​

Answer 1

Answer:

R = 220^2/100 Ω = 484 Ω. This is the resistance of the bulb. When V = 110 V, power consumed = V^2/R = 110^2/484 = 25 W. So, 25 W power is consumed when it is operated on 110 V.

make as brilliant .......

Answer 2

${\huge{\pink{\underline{\underline{Answer:}}}}}$

$\mathbb\blue{given}$

Power ( P ) = 100 W

Potential difference ( V ) = 220V

Resistance ( R ) = ?¿

$\mathbb\red{We...know}$

P = V² / R

So ;

R = V² / P

R = 220 × 220 / 100

R = 484Ω

$\mathbb\purple{Now:)}$

To find :

Current ( i ) = ¿?

V′ = supplied voltage

i = V′ / R

i = 110 / 484

i = 0.2272A

So ; The voltage drop across the bulb is 110V

The power consumed by the bulb,

P¹ = power of bulb

P¹ = V² / R

P¹ = 110 × 110 / 484

P¹ = 25 W

$\huge\mathfrak\white{Ans=25W}$