Question

The power of a bulb is 60 milliwatt and the
wavelength of light is 6000 Å. Calculate the
number of photons sec. emitted by the bulb ?
nhv = Power
or
nhc
=P
2
0-10​

Answer 1

Answer:

n=Pλhc=60×10-3×6000×10-106.62×10-34×3×108 photon/sec. =1.8×1017 Photon/sec.