The power of a combination of two lenses X and Y is 5 D . If the focal length of lens X be 15 cm :
a) calculate the focal length of lens Y.
b) State the nature of lens Y .
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Answered by
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Focal length of lens X = 15 cm = 0.15 m
Power of lens X
= 1/0.15
= 100/15
= 20/3
= +6.66 D
Power of Combination of lenses X & Y
= power of lens X + power of lens Y
5 = 6.66 + Power of lens Y
Power of lens Y
= 5-6.66
= -1.66 D
----------------------------------------------
(a) Focal length = 1/Power
f = 1/(-1.66)
f = -0.6 m
f = -60 cm
------------------------------------–-------
(b) As the focal length of lens Y is negative hence the nature of lens is Diverging lens, that is Concave lens.
_________________________
Power of lens X
= 1/0.15
= 100/15
= 20/3
= +6.66 D
Power of Combination of lenses X & Y
= power of lens X + power of lens Y
5 = 6.66 + Power of lens Y
Power of lens Y
= 5-6.66
= -1.66 D
----------------------------------------------
(a) Focal length = 1/Power
f = 1/(-1.66)
f = -0.6 m
f = -60 cm
------------------------------------–-------
(b) As the focal length of lens Y is negative hence the nature of lens is Diverging lens, that is Concave lens.
_________________________
aasthajain1:
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