The power of a combination of two lenses x and y is 5d if the focal length of lens xb 15 cm calculate the focal length of a lens by
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Given: Combined power of two lenses X & Y, (P) = 5 d
Let the combine focal length of lenses X & Y, be 'F'.
Let F1 and F2 be the focal length of lens X and Y respectively.
Here, the focal length of lens X is given as F1 = 15 cm
Relation between power and focal length is given as
F = 1 / P
Since, the lens having power 1 d (diopter) always has focal length 100 cm
So, F = [1 / ( 5 / 100)] cm
or, F = 20 cm
Now, we shall calculate the focal length of lens 'Y'.
Concept: when two lenses are in contact to each other, then the relation between their focal lengths and combined focal length is given as,
(1 / F) = (1/F1) + (1 / F2)
Or, (1 /F2) = (1/F) - (1/ F1)
Or, ( 1/ F2) = (1 / 20cm) - (1/15 cm)
Or, F2 = - 60 cm
Hence, the focal length of second lens 'Y' will be 60 cm and the nature of the lens will concave just because of having negative sign.
Let the combine focal length of lenses X & Y, be 'F'.
Let F1 and F2 be the focal length of lens X and Y respectively.
Here, the focal length of lens X is given as F1 = 15 cm
Relation between power and focal length is given as
F = 1 / P
Since, the lens having power 1 d (diopter) always has focal length 100 cm
So, F = [1 / ( 5 / 100)] cm
or, F = 20 cm
Now, we shall calculate the focal length of lens 'Y'.
Concept: when two lenses are in contact to each other, then the relation between their focal lengths and combined focal length is given as,
(1 / F) = (1/F1) + (1 / F2)
Or, (1 /F2) = (1/F) - (1/ F1)
Or, ( 1/ F2) = (1 / 20cm) - (1/15 cm)
Or, F2 = - 60 cm
Hence, the focal length of second lens 'Y' will be 60 cm and the nature of the lens will concave just because of having negative sign.
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