Question

the power of a concave lens used for correcting a miopic eye is -0.6 D. find far point of the eye​

Answer 1

Answer:

Myopia may be corrected with lenses. Concave lenses are used here. They spread the light out before it reaches the convex lens in the eye, therefore letting the image focus directly on the retina. Hyperopia is known to you probably as farsightedness.

Answer 2

The far point of the eye is 21.7 cm.

Explanation:

In Myopia (nearsightedness), eye of a person can see clearly near by objects but far objects cannot be see clearly.  

The distance of the object should be 25 cm (least distance of distinct vision).

Given, P = -0.6 D.

so focal length,

$f=\frac{1}{P}=\frac{1}{-0.6D}$

f = -1.67 m .

Use lens formula,

$\frac{1}{f}=\frac{1}{v}+\frac{1}{u}$

Here, v is the image distance and u = -25 cm = -0.25 m object distance.

substitute the values, we get

$\frac{1}{-167cm} =\frac{1}{v}+\frac{1}{25cm}$

$\frac{1}{v} =\frac{1}{-167cm} -\frac{1}{25cm}$

$\frac{1}{v}=-0.00599-0.04=-0.4599cm$

$v=\frac{1}{-0.04599cm}$

v = 21.74 cm

Thus, the far point of the eye is 21.7 cm.

#Learn More: lens formula.

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