Question

The power of a lens is + 1.5 D. Name the type of defects vision that can be corrected by using this lens. Find the focal length of the lens.

Answer 1

Answer:

The defect of vision is hypermetropia.

It can be corrected by using convex lens .

The focal length of lens will be

P=1/f

f =1/P

f=1/1.5

f=0.66

Explanation:

Answer 2

since the lens has positive power therefore the type of defect of vision is hypermetropia .

Power is the reciprocal of the focal length of the lens

1.5 = 1/f

f=1/1.5

f= 2/3

f= 0.66... m = 0.67m