Question

The power of a motor is 200w. If the unit of length is halved,that of mass is doubled and that of time is also doubled,then the power of the motor in the new system is

Answer 1

Answer:

power done is equal to work done by time is equal to m1l2t-3

Explanation:

2kg×1/2×2/2s^3

200=1/2/8=3200kgms^2/s^3

Answer 2

Explanation:

Given The power of a motor is 200 w. If the unit of length is halved,that of mass is doubled and that of time is also doubled,then the power of the motor in the new system is

• We need to solve by the concept of unit dimension.
• So power = work / time
• Work = force x displacement
•          = MLT^-2 L
•          = ML^2T^-2
• So Power = ML^2T^-2 / T
•  So P = ML^2 / T^3
• So we have unit concept
• So n1 U1 = n2 U2
•     200 x ML^2 / T^3 = n2  
• (here mass is doubled and it will be 2m and length will be L^2 / 4)
•   So 200 x ML^2 / T^3 = n2 x L^2 / 4 / 8 T^3
•      So n2 = 200 x 8
•     Or n2 = 3200 W
• So the power will be 3200 Watts

Reference link will be

https://brainly.in/question/6771489