the power of a motor pump is 5 kilowatt . how much water per minute the pump can raise to a height of 20 m ( g = 10 m/s 2 )
Answers
Answered by
7
Average power, P = change in energy (∆E)/ time taken(∆t).
Hence, ∆E = P∆t
→ mg∆h=P∆t
From given values,
→ m(10)(20) = 5000(60)
→ m = 1500 Kg
Hence, ∆E = P∆t
→ mg∆h=P∆t
From given values,
→ m(10)(20) = 5000(60)
→ m = 1500 Kg
pinky18:
actually the answer is 1500kg ....i dont know how to do ..
Sorry, I mistook it for watt.
So, OK now?
answer??
i dont know how to do it ...
That's the formula you just put the given things in it. Answer is 1500 Kg.
ya i understood ..
thanks ..
Similar questions