Physics, asked by Shanu191, 1 year ago

The power of a pump motor is 2 kw. How much water per minute can it raise to a height of 10 m? (g-10 m/s) [1200 kg)

Answers

Answered by ShivamKashyap08
11

\huge{\bold{\underline{\underline{....Answer....}}}}

\huge{\bold{\underline{Given:-}}}

  • Power of Pump (P) = 2KW = 2000 Watts.
  • Height (H) = 10 meters.
  • Acceleration due to gravity (g) = 10 m/s².
  • Time (t) = 1 minute = 60 seconds.

\huge{\bold{\underline{Explanation:-}}}

\rule{300}{1.5}

Firstly Finding the Work done.

Work Done:-

It is defined as The scalar Product of Force and Displacement.

From the Formula,

\large{\boxed{\tt W = F.s}}

But

  • F = mg = Weight of the body.
  • s = h = Height raised.

Therefore,

\large{\tt \leadsto W = mg \times h}

\large{\tt \leadsto W = mgh}

Substituting the values,

\large{\tt \leadsto W = m \times 10 \times 10}

\large{\tt \leadsto W = m \times 100}

\large{\tt \leadsto W = 100m \: -----(1)}

\rule{300}{1.5}

\rule{300}{1.5}

Now,applying Power Concepts,

Power:-

Power is defined as rate of doing work.

It can be expressed as,

\large{\boxed{\tt P = \dfrac{W}{t}}}

Substituting the values,

\large{\tt \leadsto2000 = \dfrac{100m}{60}}

\large{\tt \leadsto 2000 \times 60 = 100m}

\large{\tt \leadsto 120000 = 100m}

\large{\tt \leadsto m = \dfrac{120000}{100}}

\large{\tt \leadsto m = \cancel{\dfrac{120000}{100}}}

\huge{\boxed{\boxed{\tt m = 1200 \: Kg}}}

So, the water raised per minute is 12 Kilograms.

\rule{300}{1.5}

Answered by mahroz39
0

Power=Work/Time

     P=Weight/t ime

     P=mgh/t ime

   2000=m×10×10/60

   hence

    m=20×60=1200 kg=1200 L

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