Question

The power of an electric bulb connected to 220V source when the current through a filament is 0.05 amp is​

Answer 1

220 * 0.05 = 11 watts power

Answer 2

Bulb is connected to 220 Volts potential difference and current flowing through it is 0.05 Amperes.

Now, power dissipated in bulb :

$P = V \times I$

$\implies P = 220 \times 0.05$

$\implies P = 11 \: watt$

So, 11 watt of power is dissipated in bulb.