The power of an electric motor if it lifts 200kg of water in 5 min from a well
120 m depth is____W ((Take g = 9.8m/s?)
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Required Answer :
The power of an electric motor if it lifts 200kg of water in 5 min from a well 120 m depth is 784 W
Given :
- Mass = 200 kg
- Time = 5mins
- Height = 120 m
- Gravity = 9.8 m/s²
To find :
- Power of the electric motor
Solution :
Firstly, we shall convert the time from minutes into seconds.
As we know,
- 1 min = 60 seconds
So, in order to convert the time from minutes into seconds, multiply it by 60.
→ Time = 5 mins
→ Time = 5 × 60
→ Time = 300 seconds
Formula to calculate power :-
- Power = work/time and
- Power = mgh/time
Substituting the given values :-
→ Power = (200 × 9.8 × 120) ÷ 300
→ Power = (200 × 98 × 120) ÷ 300 × 10
→ Power = (2 × 98 × 12) ÷ 3
→ Power = (2 × 98 × 4)
→ Power = 784
Therefore, the power of the electric motor = 784 W
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