The power of an engine is 20 kilowatt . What time will be taken in lifting 100 kg body to a height of 50 m ? (ans: 2.5 sec)
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Answered by
13
given that m = 100 kg , h = 50 m, g=10 ms^-2
p= mgh/t
t= mgh/p
t=100×10×50/20×10^3
t= 2.5 sec
hence ans is 2.5 sec
I hope it help you
p= mgh/t
t= mgh/p
t=100×10×50/20×10^3
t= 2.5 sec
hence ans is 2.5 sec
I hope it help you
Answered by
7
We used the formula of P=W/T..... Hope it helps
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