The power of an engine that lifts 10^5 kg of coal per hour from a mine of 360 m deep is
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Height (h) = 360m
Acceleration due to gravity = 10 m/s^2
Time(t) = 1 hour = 3600 s
Then,
P.E = mgh
= 10^5 * 10 * 360 J
Work done = P.E = 10^5 * 10 * 360 J
We know,
Power = Work done / Time
= 10^5 x 10 x 360/3600
= 10^5 watt.
Acceleration due to gravity = 10 m/s^2
Time(t) = 1 hour = 3600 s
Then,
P.E = mgh
= 10^5 * 10 * 360 J
Work done = P.E = 10^5 * 10 * 360 J
We know,
Power = Work done / Time
= 10^5 x 10 x 360/3600
= 10^5 watt.
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