the power of lens is +5 D .what is the nature and focal length of this lens should an object be placed so as to get its inverted image of same size
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9
f=1/5
=0.2m
=20cm
Nature of image real, inverted and same size of the object.
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3
f = 1/5 =0.2m =20cm. Nature of image real, inverted as well as same size of the object. Power of lens (P) = – 2.0 D Thus, focal length = (f)
We know that, P = (1/f)
– 2.0 D = (1/f)
f = (1/– 2.0) D
Focal length (f) = – 0.5 m
Power of length is (-ive), therefore it is a concave lens.
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