Question

The power of lens used by short sighted person is -2D . Find the maximum Distance of an object which he can see without spectacles?​

Answer 1

Explanation:

The answer of the question is - 50 cm

Solution refer in Attachment.

Thank you

Answer 2

Explanation:Givenu = ∞ | v = ? | P = -2 D$u = ∞ | v = ? | P = -2 D$we know that,$\frac{1}{f} \: = \frac{ 1}{v} \: - \frac{1}{u}$And also,$P = \frac{1}{f} \:$By substitution, we get$P = \frac{ 1}{v} \: - \frac{1}{u}$$-2 = \frac{ 1}{v} \: - \frac{1}{∞}$$v \: = \frac{ 1}{-2} \:- 0$$v \: = -0.5 m$v = -0.5 meter = - 50 cm

$HOPE -IT -HELPS -MAKE -ME -BRAINLIEST$