Question

The power of lifting a stone of mass 10 kg and specific gravity 3 from the bed of a lake to height of 6m
in water in 9.8 sis_ _x 10 w​

Answer 1

Answer:

Explanation:

Hey mate your question is incomplete

Answer 2

The work done is 391.8 J.

Explanation:

Given that,

mass of stone = 10 kg

Specific gravity = 3

Height = 6 m

Suppose calculate the work done .

We need to calculate the mass of an equal volume of water

Using formula of specific gravity

$\text{specific gravity}=\dfrac{\text{mass of stone in air}}{\text{ mass of an equal volume of water}}$

$\text{ mass of an equal volume of water}=\dfrac{\test{mass of stone in air}}{\text{specific gravity}}$

Put the value into the formula

$\text{ mass of an equal volume of water}=\dfrac{10}{3}$

We need to calculate the apparent weight of stone in water

Using formula of weight

$W_{a}=W_{s}-W_{d}$

Put the value into the formula

$W_{a}=10-\dfrac{10}{3}$

$W_{a}=6.67\ kg$

We need to calculate the applied force

Using formula of force

$F=mg$

Put the value into the formula

$F=6.67\times9.8$

$F=65.3\ N$

We need to calculate the work done

Using formula of work done

$W=F\times d$

$W=65.3\times6$

$W=391.8\ J$

Hence, The work done is 391.8 J.

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Topic : work done

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