Question

The power of the concave lens is 0.05 cm. At what distance should the object from the lens be
placed so that it forms an image at 10 cm from the lens ?​

Answer 1

distance should the object from the lens is 0.100502513 m or ~ 10.05 cm

power of concave lens, P = -0.05 D [ by mistake you had written 0.05 cm ]

as power is inverse of focal length.

so, 1/f = P = -0.05 D

⇒f = -1/0.05 = -20 m

image distance, v = -10cm = -0.1 m

using formula, 1/v - 1/u = 1/f

⇒1/-0.1 - 1/u = 1/-20

⇒1/u = -10 + 1/20

⇒1/u = (-199)/20

⇒u = -20/199 = -0.100502513 m

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Answer 2

$\huge\bold\purple{Answer:-}$

focal length =f=-15 cm after sign conventions

image distance=V=-10cm

object distance=?

by lens formula:

1/f=1/v-1/u

1/u=1/v-1/f

= -1/10+1/15

= -3+2/30

=-1/30

u=-30cm

Magnification=m=v/u

=-10/-30=1/3=0.33