Question

the power of torch bulb rated at 2.5 v and 500 metre empier ​

Answer 1

Answer :-

V = 2.5 V

I = 500mA

I = 500/1000 = 0.5A

→ P = VI

→ P = 2.5 × 0.5

→ P = 1.25 W

• Resistivity :

Resistivity of conductor is defined as the resistance offered by a conductor having a unit length and unit area of cross section.