The power of two lenses are +12d and -2d. they are placed in contact on the same axes. what will be the focal length of the combination?
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Answer:
The focal length of the combination is = 10 cm.
Explanation:
The focal length of the first lens = 1 / 12 m = 0.083333 m
The focal length of the second lens = - 1/2 m = 0.5 m
If ' f ' be the focal length of the combination then
1/f = ( 1/0.08333 ) - ( 1/ 0.5 )
= 10
So f = 1/10 m = 0.1 m = 10 cm
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