the power output of an engine is 3 kW. how much work does the engine do in 20 second
Answers
Answered by
207
Power output of an engine = 3kW = 3000W
Time taken = 20 seconds
Energy consumed = work done
Let work done be W.
Power = Work done/ Time taken
3000 = W/20
3000 x 20 = W
W = 60000 J
Hence Work done = 60000 J = 60 kJ.
Time taken = 20 seconds
Energy consumed = work done
Let work done be W.
Power = Work done/ Time taken
3000 = W/20
3000 x 20 = W
W = 60000 J
Hence Work done = 60000 J = 60 kJ.
Answered by
0
The engine does 60000 joules of work in 20 seconds.
To calculate the work done by an engine, we can use the formula:
work = power x time
In this case, we know that the power output of the engine is 3 kW (kilowatts) and the time is 20 seconds.
So, we can plug in these values into the formula:
work = 3 kW x 20 seconds
To get the work done in Joules we need to convert kW to W (watts)
1 kW = 1000 W
so,
work = 3000 W x 20 seconds = 60000 J (joules)
Therefore, the engine does 60000 joules of work in 20 seconds.
To know more about work visit
https://brainly.in/question/12207321
https://brainly.in/question/29618011
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