Question

The power p in an electric circuit varies directly as the square of the current I. If p is 100 when I = 5, find p when I = 4.

Answer 1

Answer:

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Electricity. The power P in an electric circuit varies directly with the square of the current I. If P = 46 when I = 2, find P when I = 5.

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P = I^2*R

46 = 4*R

R = 23/2

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find P when I = 5.

P = 25*23/2

P = 575/2 watts

Answer 2

Answer:

it's is given that p is directly promotional to I²

Step-by-step explanation:

p = kI²

where k is a constant

so p = k i²

$\frac{p1}{p2} = \frac{ {i1}^{2} }{ {i2}^{2} }$

we know that p1 = 100, i1 = 5 , i2 = 4

so,

$p2 = p1 \times \frac{ {i2}^{2} }{ {i1}^{2} }$

$p2 \: = 100 \times \frac{16}{25}$

so p2 = 64