The power required in lifting a mass of 500 kg to a height of l6m in 30s
Answers
Answered by
1
Answer:
2613.33 W
Explanation:
Power = energy/time
Power = mgh/30
= 500×9.8×16/30
= 2613.33 W
Answered by
1
Answer:
force= mg
force=500*10=5000N
work=F*S=5000*16=80000J
power=work/time
power=80000*60/30 // we change sec into min
power=160000W
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