Question

The preceeding term of 13 in an Arithmetic progression 13, 10, 7……. Is​

Answer 1

Answer:

What is the next three terms of each sequence 13, 10, 7, 4, and 1?

This sequence is formed by subtracting 3 from the previous term.

13–10=3

10–7=3

7–4=3

4–1=3

Let the other 3 terms be termed as a,b,c

For a

1–a=3

1–3=a

a=-2

For b

-2-b=3

-2–3=b

b=-5

For c

-5–c=3

-5–3=c

c=-8

The next 3 consective terms are

-2, -5, -8

Answer 2

Answer:

the preceeding terms are 17,20,23 ,27,30,33 and so on