The precipitate of caF2( ksp=1.7×10*10)is obtained when equal volumes of the following are mixed?
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Answer:
The precipitate of CaF
2
(K
sp
=1.7×10
−10
) is not obtained when equal volumes of 10
−4
MCa
2+
+10
−4
MF
−
are mixed. This is because ionic product of calcium fluoride will not exceed solubility product.
Q=[Ca
2+
][F
−
]
2
Q=0.5×10
−4
×(0.5×10
−4
)
2
Q=1.3×10
−13
K
sp
=1.7×10
−10
1.3×10
−13
<1.7×10
−10
Q<K
The precipitate of CaF
2
(K
sp
=1.7×10
−10
) is obtained when equal volumes of 10
−2
MCa
2+
+10
−3
MF
−
are mixed. This is because ionic product of calcium fluoride will exceed solubility product.
Q=[Ca
2+
][F
−
]
2
Q=0.5×10
−2
×(0.5×10
−3
)
2
Q=1.3×10
−9
K
sp
=1.7×10
−10
1.3×10
−9
>1.7×10
−10
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