The premeter of ends of a frustum of a cone is 44cm and 8.4 πcm.If depth is 14 cm
Find its volume
Answers
Answer:
1408 cm2
Step-by-step explanation:
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MATHS
The perimeter of the ends of a frustum of a cone are 44cm and 8.4πcm. If the depth is 14cm, then find its volume.
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ANSWER
We have,
Perimeter of the ends of the frustum cone
2πR=44 cm⇒R=7 cm
2πr=8.4π cm⇒r=4.2 cm
depth(h)=14 cm
We know that the volume of the frustum cone
=
3
1
π(R
2
+r
2
+Rr)h
So,
=
3
1
×
7
22
(7
2
+(4.2)
2
+7×4.2)×14
=
3
1
×22×(49+17.64+29.4)×2
=
3
44
×(96.04)
=1408.6 cm
3
Answer:
We have,
Perimeter of the ends of the frustum cone
2πR=44 cm⇒R=7 cm
2πr=8.4π cm⇒r=4.2 cm
depth(h)=14 cm
We know that the volume of the frustum cone
= 1/3π(R 2 +r 2 +Rr)h. (bro yaha par 2 ka mean. )
( square hai)
So,
= 1/3 × 7/22 (7*7+(4.2)(4.2) +7×4.2)×14
= 1/3×22×(49+17.64+29.4)×2
= 44/3 ×(96.04)
=1408.6 cm3(cm cube)
Hence, the this is the answer
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