Question

The prependicular bisectors of the sides of a triangle ABC meet at I
Prove that : IA = IB = IC . only correct answers I want. If you are know then only answer please​

Answer 1

Answer:

This can be proved by congruency of triangles but before this triangle ABC should be equilateral.

Answer 2

Answer:

Heya your answer ❤

Step-by-step explanation:

Given : In ΔABC, ID, IE, IF are perpendicular bisector of side BC, AC and AB respectively and I is the circumcentre of ΔABC

Now in ΔIBD and ΔICD

BD=DC [ID is the bisector of BC]

ΔIBD=ΔIDC=90°[ID is the perpendicular to BC]

ID=ID [common]

T

hus ΔIBD ~=ΔICD [ By SAS rule]

= IB=IC....... 1

similarly

ΔAIE~=ΔCIE

= AI=IC....2

from 1 and 2

IA=IB=IC

Hence proved

hope it's will help u

$answer \: by \: eric \: taeyong$