the presen
The count of bacteria in a certain experiment increased at the rate of 6% per hour. Find the count of
bacteria at the end of 3 hours, if it was 45,00,000 in the beginning.
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Answer:
We have, P
0
= Original count of bacteria =506000,
Rate of increase =R=2.5% per hour,
Time =2 hours
∴ Bacteria count after 2 hours = P
P=P
0
(1+
100
R
)
T
=506000×(1+
100
2.5
)
2
=506000×
100
102.5
×
100
102.5
=531616.25=531616 (approx)
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