Math, asked by vksntl52, 8 months ago

The present age of a and b are in ratio 4 ratio 3 four years later their ages will be in a ratio 6 ratio 5 what are their present ages

Answers

Answered by abhi569
18

Answer:

12 and 9 year

Step-by-step explanation:

Let the present age of A be '4a' and that of B be '3'.

          After 4 years:

Age of A = 4a + 4

Age of B = 3a + 4

   In question,  that time"

⇒ age of A : age of B = 6:5

⇒ (4a + 4)/(3a + 4) = 6/5

⇒ 5(4a + 4) = 6(3a + 4)

⇒ 20a + 20 = 18a + 24

⇒ 20a - 18a =24 - 20

⇒ 2a = 4

⇒ a = 4/2 = 2

     Age of A = 4a = 4(2) = 8 year

                 B = 3a = 3(2) = 6 year

Answered by Anonymous
110

⚜ Given :-

Present age of A and B are in ratio 4:3.

After four years, their ages will be in a ratio 6:5.

⚜ To Find :-

Present Ages Of A And B.

⚜ Solution :-

Let,

The Present Age Of A = 4x.

The Present Age Of B = 3x.

It is Given that,

Four years later, their ages will be in a ratio 6:5.

So,

According To Question,

4x+4/3x+4 = 6/5.

➠ 6(3x+4) = 5(4x+4).

➠ 18x + 24 = 20x + 20.

➠ 18x - 20x = 20 - 24.

➠ -2x = -4.

➠ x = 2.

Hence,

Age Of A = 4x = 8.

Age Of B = 3x = 6.

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