Question

The present age of A and B are in ratio 9:4. Seven years hence the ratio of their ages will be 5:3. Find their present ages.

Plz... solve it...​

Answer 1

Answer:

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Answer 2

Answer:

The present age of A=18

Hence the present age of B=8

Step-by-step explanation:

Let the age of A be=9x

Let the age of B be =4x

According to the Question, Seven years later the ratio of their ages will be 5:3. So,

9x+7=5x

  by

4x+7=3x

by cross multiplication, we have

3x(9x+7)=5x(4x+7)

27$x^{2}$+21x=20$x^{2}$+35x

27$x^{2}$-20$x^{2}$=35x-21x

7$x^{2}$=14x

$x^{2}$=14x/7

x multiplied by x =14x/7

x multiplied by x =2x

x=2x/x

x=2

Hence the present age of A=9x=9(x)=9(2)=18

Hence the present age of B=4x=4(x)=4(2)=8