Question

the present age of a and b are in the ratio 7:5 . ten years later the ages will be in ratio 9 : 7 find the present age?
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Answer 1

Answer:

Here is your answer ----

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Let the age of A be 7x

Let the age of B be 5x

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ATQ -----

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=> (7x + 10) : (5x + 10) = 9 : 7

=> (7x + 10) / (5x + 10) = 9 / 7

=> 7 (7x + 10) = 9 (5x + 10) [Cross multiplication)

=> 49x + 70 = 45x + 90

=> 49x - 45x = 90 - 70

=> 4x = 20

=> x = 20 / 4

=> x = 5

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• A's present age = 7x = (7×5) years = 35 years

• B's present age = 5x = (5×5) years = 25 years

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here is your answer mate !

Step-by-step explanation:

Answer 2

Answer:

Let the present age of a be 7x and that of b be 5x

so,

after 10 years,

a's age will be 7x+10

b's age will be 5x+10

so,

(7x+10):(5x+10) = 9:7

$\frac{7x + 10}{5x + 10} = \frac{9}{7} \\ = > 7(7x + 10) = 9(5x + 10) \\ = > 49x + 70 = 45x + 90 \\ = > 49x - 45x = 90 - 70 \\ = > 4x = 20 \\ = > x = \frac{20}{4} \\ = > x = 5$

so, a's present age is 7x years or 7×5 or 35 years

b's present age is 5x years or 5×5 or 25 years

Hope this helps you.