Question

The present age of a boy is obtained by 2 times his age after 2 years, subtracted
by 2 times his age before 2 years. Find his present age *​

Answer 1

Answer:let the present age of the boy be 'x'.

If his age is obtained by 2 times his present age then, 2x+2 is the equation.

Then if it is subtracted by his age before 2 times his age 2 years before, 2x-2 is the equation.

According to the given information,

x=(2x+2) -(2x-2)

x=2x+2-2x+2

x=2+2

x=4

Step-by-step explanation:

Answer 2

Let the present age of the boy is $x$ years.

If his age is obtained by 2 times his present age then his expression is $2x+2$ .

And if it is subtracted by his age before 2 times of his age 2 years, then the expression will be $2x-2$ .

therefore, according to the given condition, we get

$x=(2x+2)-(2x-2)\\\Rightarrow x=2x+2-2x+2\\\Rightarrow x=2x-2x+2+2\\\Rightarrow x=2+2\\\Rightarrow x=4$

Therefore, the present age of the boy is 4 years.

To learn more about linear equations from the given link

https://brainly.in/question/3145580

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