Question

The present age of a boy is three times
present age of his brother. After five yus
ther age add to 66 years Find the present
age.​

Answer 1

Answer:

Step-by-step explanation:

The present age of a boy = x

age of his brother.= 3x

given sum of their ages after five years is 66

                          ⇒(x+5)+(3x+5)=66

                             4x+10=66

                            4x=66-10

                            4x=56

                               x=56/4

                            x=14

sahil's age is  x=14=14 years

 sahil's mother age is 3x=3(14)=  42=42years

Answer 2

Step-by-step explanation:

let the age of his brother be X and his age be 3x

after 5 years

boy's age =3x+5

brother age = x+5

a/q,

3x+5+x+5=66

4x +10=66

4 x = 66-10 or 56

x = 56÷4

x=14

hence

brother age = 14

boy's age = 3×14=42